Question

If the electronic configuration of calcium is [Ar]4s2 then what will be the electronic (4) configuration of chromium and free dipositive manganese ion?

Answer 1

electronic configuration of chromium is
1s2 2s2 2p6 3s2 3p6 3d5 4s1

Answer 2

Explanation:

Atomic number of chromium is 24 and its electronic configuration is as follows.

     $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}3d^{5}$

Whereas the atomic number of manganese is 25 and electronic configuration of manganese is as follows.

    $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{5}$

Thus, the electronic configuration of free dipositive manganese ion $(Mn^{2+})$ is as follows.

     $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{0}3d^{5}$