Question

If the energy of first Bohr orbit is,-13.58eV,then the energy of first orbit of 3Li^2+ will be, a)-40.74eV b)-122.22eV c)-54.32eV d)13.58eV.

Answer 1

apply formula i.e -13.6ev/atom with z square/n square.n here is 1 and z is 3 .so multiply -13.58 with 3 square i.e 9.answer will be -122.22 ev/ atom