If the factors of a² + b² + 2(ab + bc + ca) are (a + b + m) and (a + b + nc), then the value of (m + n) is:
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the value of m is 0 and that of n is 2 hence the answer is 2.
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a² + b² + 2(ab + bc +
ca) = a² + b² + 2ab +2c(a+b) = (a+b)²+2c(a+b) =(a+b)(a+b+2c) now, (a + b + m)=(a + b + 0) and (a + b + nc)=(a + b + 2c)
then the value of (m + n)=(0+2)=2
ca) = a² + b² + 2ab +2c(a+b) = (a+b)²+2c(a+b) =(a+b)(a+b+2c) now, (a + b + m)=(a + b + 0) and (a + b + nc)=(a + b + 2c)
then the value of (m + n)=(0+2)=2
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