Question

If the far point of eye lens is 10 m, find power of the lens required to correct the defect.

Answer 1

Answer:

f = Focal length of eye, y = shifted far point, P = power of lens required.

Now,

1/f = 1/25 - 1/y

convert into meter 

1/f = 4 - 1/10

1/f = (40 - 1)/10

1/f = 39/10

1/f = P = 3.9 Dioptre. ANSWER.

thanks...

Explanation: