Question

if the force of an electric field on 5C charge is 10N, the intensity of field is?

Answer 1

hey here is your answer...
we know F=qE
here F=10 N
q= 5C

so E= 10 / 5
. E= 2 N/C

hope this helps in better way.plz mark it brainliest.

Answer 2

FIELD INTENSITY IS 2 N/C.

Given:

• Force on 5C charge is 10N.

To find:

Electrostatic field intensity at that point ?

Calculation:

Electrostatic field intensity is defined as the force experienced by a unit positive charge at a particular point.

So, we can say :

$E = \dfrac{F}{q}$

• E is electrostatic field intensity, F is the electrostatic force and q is the charge.

$\implies E = \dfrac{10}{5}$

$\implies E = 2 \: N/C$

So, the field intensity at that point is 2 N/C.