If the function f : {-1, 1} → {0, 2} defined by f(x) = ax + b is a surjection, then find a and b.
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Answer:
a = 1, b =1
Step-by-step explanation:
Concept:
A function f from set A to set B is called surjective if range of f is equal to co-donain(B)
Given: f(x) = ax +b
Since f is surjective,
Range = co-domain = { 0, 2}
f(-1) = 0 , - a + b = 0.....(1)
f(1) = 2, a + b = 2.....(2)
(1)+(2) 2b = 2
b = 1
put b=1 in (2) we get a = 1
I hope this answer helps you
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