Question

If the function f given by f(x) = x³ – 3(a – 2)x² + 3ax + 7, for some a ∈ R is increasing in (0, 1] and decreasing in [1, 5), then a root of the equation, [f(x) – 14]/(x – 1)² = 0
(x ≠ 1)
is :
(A) –7 (B) 5
(C) 7 (D) 6

Answer 1

Answer:

option c must be the answer