Question

if the graph of equation 2 X + k y= 10k and intersect X-axis at the point (5,0) what is the value of k

Answer 1

As the equation 2x + ky=10k cuts the x axis at point (5,0) therefor the point must satisfy it.
Therfore, 2*5+k*0=10k
10=10k
Therfore, k=10

Answer 2

2x+ky =10k 

put the value of x and y from (5,0)

x= 5 and y = 0

then 2*5+k*0 = 10k

10 = 10k

k=10/10

k=1