Question

if the HCF of 408 and 1032 is expressible in form 1032y-408×5,then find y​

Answer 1

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At first, we need to find HCF of 1032 And 408

HCF is

• 1032 > 408

• 1032 = 408 × 2 + 216

• 408 = 216 × 1 + 192

• 216 = 192 × 1 + 24

• 192 = 24 × 8 + 0

• HCF = 24

Now, According to question -

• 1032y - 408 × 5 = 24

• 1032 - 2040 = 24

• 1032y = 2040 + 24

• 1032y = 2064

• y = 2064/1032

• y = 2

Hence,

the value of y is 2.

Answer 2

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