If the horizontal component of 60N force is 30N,what will be the vertical component?
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GIVEN:-
resultant force = 60N =F
➡horizontal component of force
=F cosθ =30N
=> Fcosθ =30
=> 60cosθ =30
=> cos θ =30/60 =1/2
=> cosθ = cos60°
=>θ = 60°
➡we know that vertical component of force :-
= Fsinθ
= 60 × sin60°
= 60 ×(√3)/2
= 30√3 N
hope it helps you...
☺☺
resultant force = 60N =F
➡horizontal component of force
=F cosθ =30N
=> Fcosθ =30
=> 60cosθ =30
=> cos θ =30/60 =1/2
=> cosθ = cos60°
=>θ = 60°
➡we know that vertical component of force :-
= Fsinθ
= 60 × sin60°
= 60 ×(√3)/2
= 30√3 N
hope it helps you...
☺☺
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