if the horizontal range of a projectile is twice of the maximum height attained find the angle of projection...
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3
Answer:
Range = u^2 x sin2Θ/g
Height maximum = u^2 x sin^2Θ/2g
According to question
Range = 2 x height
u^2 x sin2Θ/g = 2 x u^2 x sin^2Θ/2g
=sin2Θ = sin^2Θ
= 2sinΘcosΘ = sin^2Θ
= tanΘ = 2
= Θ =tan^-1(2)
Answer= Θ =tan^-1(2)
hope it helped
Step-by-step explanation:
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Answer:
Iron rods a,b,c,d,e and f are making a design in a bridge as shown in the figure if a||b , c||d , e||f, find the marked angles between
¡ b and c
¡¡ d and e
¡¡¡ d and f
¡v c and f
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