Question

If the if the sum of three consecutive even numbers is 660 find the numbers

Answer 1

Let the numbers be 2y, 2y+2 and 2y +4
$6y = 660 - 6 \\ y = 109 \\ 2y = 218$
The numbers are 218, 220 and 222

Answer 2

Answer:

Let the required numbers be x, (x+2) and (x+4).

Atq,

$\: \: \: \: \: \: \: \: x + (x + 2) + (x + 4) =6 60 \\ = > x + x + 2 + x + 4 = 660 \\ = > 3x + 6 = 660 \\ = > 3x = 6 60 - 6 \\ = > 3x = 654 \\ = > x = \frac{654}{3} \\ = > x = 218$

Hence, the required numbers are 218, (218+2) = 220 and (218+4) = 222.