Question

if the intensity of an X-ray becomes I0/3 from I0 after traveling 3.5 cm inside a target ,then its intensity after traveling next 7 cm will be?

Answer 1

Intensity of X rays after traversing a distance x is given by I = I0e−μx, where I0 is the initial intensity of X rays and μ the absorption coefficient. From the data given, we can write I0/3 = I0e−3.5μ ⇒ 1/3 = e−3.5μ 3 = e3.5μ ln 3 = 3.5 μ 1.0986 = 3.5 μ ⇒ μ = 0.313885 cm−1 When x = 3.5 cm + 7 cm = 10.5 cm, the intensity is I = I0e−μx = I0e−0.313885x 10.5, = I0e−3.2958, =.0370 I0

Answer 2

Answer:

Please find below the solution to the asked query:

Intensity decreases with distance as in the following relation,

I α 1r2

So, Given that at a distance 3.5 cm, intensity is I03, where I0 is initial intensity.

Therefore,

I α 1r2 ⇒ I = Kr2 ⇒ I03 = K I0(3.5)2⇒ K = (3.5)23

So, intensity at a distance of 7 cm is,

I' = KI0(7)2=((3.5)23)(I0(7)2)=((3.5)23)(I04(3.5)2)⇒ I' = I012

Hope this information will clear your doubts about the topic.

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Regards

Please find below the solution to the asked query:

Intensity decreases with distance as in the following relation,

I α 1r2

So, Given that at a distance 3.5 cm, intensity is I03, where I0 is initial intensity.

Therefore,

I α 1r2 ⇒ I = Kr2 ⇒ I03 = K I0(3.5)2⇒ K = (3.5)23

So, intensity at a distance of 7 cm is,

I' = KI0(7)2=((3.5)23)(I0(7)2)=((3.5)23)(I04(3.5)2)⇒ I' = I012

Hope this information will clear your doubts about the topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

RegardsExplanation: