If the ionization energy of He+ is 19.6*10^-18 J/atom, then energy of Be3+ ion in the SECOND STATIONARY STATE is what?
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E = -2.18 × 10^-18 × z^2/n^2
E = -2.18× 10^-18 × 16/4
E = -8.72 × 10^-18 J
E = -2.18× 10^-18 × 16/4
E = -8.72 × 10^-18 J
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