If the kinetic energy of a body increases by 125% it's linear momentum increases by
sincosec1:
50 percent
How?
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KE=P^2/2m
KE'=P'^2/2m
KE'=KE+1.25*KE=2.25KE
2.25KE=P'2/2m
2.25*P^2/2m=P'^2/2m
2.25P^2=P'^2
1.5P=P'
so momentum is increased by 150 percentage
KE'=P'^2/2m
KE'=KE+1.25*KE=2.25KE
2.25KE=P'2/2m
2.25*P^2/2m=P'^2/2m
2.25P^2=P'^2
1.5P=P'
so momentum is increased by 150 percentage
It's wrong
bro it is 50 %.(p'-p)/p*100=(1.5-1)*p/p*100=.5*100=50
is it ok now?
Ok
thnx
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