Question

If the kinetic energy of a particle is reduced to half, de-Broglie wavelength becomes

Answer 1

Here's your answer for the question

Answer 2

de-Broglie's wavelength becomes √2 times

according to de-Broglie's wavelength equation,

λ = h/p

where p is linear momentum of particle.

relation between linear momentum and kinetic energy is given as, K.E = p²/2m

so, λ = h/√(2mK.E)

here it is clear that, wavelength is inversely proportional to square root of kinetic energy.

now if kinetic energy of the particle is reduced to half wavelength becomes √2 times.

hence, de-Broglie's wavelength becomes √2 times

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