Question

if the length and breadth of the rectangular are 36 cm and 24 cm respectively. find its perimeter and area of rectangal.

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Answer 1

perimeter of rectangle=2(L+B)

=2(36+24)

=2(60)

=120

area of rectangle= L×B

= 36×24

=864

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Answer 2

Diagram:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 36 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 24 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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$\large\mathfrak \pink{Solution:-}$

$\underline \mathbb{GIVEN:-}$

Length = 36 cm

Breadth = 24 cm

$\underline \mathbb{TO \: FIND:-}$

The perimeter and area of the rectangle.

$\underline \mathbb{FORMULA:-}$

Area of the rectangle = Length × Breadth

Perimeter of the rectangle = 2 (length + breadth)

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

Area of the rectangle = Length × Breadth

Area =( 36 × 24) cm = $864\:cm^2$ cm

Perimeter of the rectangle = 2( Length + Breadth)

Perimeter = 2 ( 36 + 24)

Perimeter = 2 × 60 = 120 cm

$\underline \mathbb{ANSWER:-}$

Area = $864\:cm^2$ cm

Perimeter = 120 cm

$\underline \mathbb{EXTRA\: INFORMATION:-}$

$Diagonal \: of \: a \: rectangle \: = \sqrt{ {length)}^{2 } + {(breadth)}^{2} }$