Question

if the length and time period of an oscillating pendulum have errors 3% and 2% respectively,then what is the error in estimate of g​

Answer 1

Answer:  7%

Explanation:

T = 2π √l/g

Squaring both sides,

T² = 4π² l/g

=> g = 4π²l/T²

Now let's evaluate percentage error in g:

Δg/g ×100= ( Δl/l×100 + 2(ΔT/T)×100

Δg/g×100 = 1% + 2×3% = 7%