if the length of a rectangle is increased by 10% by what percent it's width will be decreased so that area remains same?
Answers
Answered by
1
Answer:
New l = l + 10/100*l
= 11 l/10
Area = l * b
11 l/10 * required width = l*b
Required width = 10*b/11
So Decrease in width = b - 10b/11
= b/11
So percent decrease = b/11*100
Hence 100/11 = 9.09 per cent has to be decreased in case of width
Answered by
1
Answer:
100/11
Step-by-step explanation:
- suppose l=1
- area l×b
- 1×b=100%
- 1+10×b=100%
- b=100/10+1
- b=100/11
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