if the length of shadow of a vertical pole on the horizontal ground is (3)^1/2 times of its hieght, then the angle of elevation of sum is...?
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Consider the height of tower be h ∴ height of shadow =√3h . In a triangle ABC,
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°. Therefore, angle of elevation is 30°.
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tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°. Therefore, angle of elevation is 30°.
hope it helps u pls mark me as brainlist answer
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