Math, asked by AST2003, 1 year ago

if the length of the sides of a right angled triangle are x-6, x+8 and x+10cm. and the area of this triangle is 120 cm^2 then find the perimeter of this triangle


hitjoshi1996: x2+(x−1)2=(x+1)2

⟹2x2–2x+1=x2+2x+1

⟹x2–4x=0

⟹x(x−4)=0

⟹x=4

Done.

Answers

Answered by adityadream111
0

x2+(x−1)2=(x+1)2x2+(x−1)2=(x+1)2

⟹2x2–2x+1=x2+2x+1⟹2x2–2x+1=x2+2x+1

x2–4x=0x2–4x=0

⟹x(x−4)=0⟹x(x−4)=0

⟹x=4

Answered by Ritamsamantaray
2
hope it helps..........
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hitjoshi1996: hi
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