if the length of the sides of a right angled triangle are x-6, x+8 and x+10cm. and the area of this triangle is 120 cm^2 then find the perimeter of this triangle
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x2+(x−1)2=(x+1)2x2+(x−1)2=(x+1)2
⟹2x2–2x+1=x2+2x+1⟹2x2–2x+1=x2+2x+1
⟹x2–4x=0⟹x2–4x=0
⟹x(x−4)=0⟹x(x−4)=0
⟹x=4
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⟹2x2–2x+1=x2+2x+1
⟹x2–4x=0
⟹x(x−4)=0
⟹x=4
Done.