Question

if the line lx+my+n=0 touches the parabola y²=4ax,prove that ln=am²

Answer 1

We can write lx + my + n = 0 in the form of y = Mx + c

So, my = -lx - n
y = -lx/m - n/m

Comparing with y = Mx + c,
M = -l/m
c = -n/m

We know that c = a/M
Mc = a

Putting the values of M and c,
-l/m x - n/m = a
ln/m^2 = a
ln = am^2

Hope This Helps You!

Answer 2

Answer:

Step-by-step explanation:

We can write lx + my + n = 0 in the form of y = Mx + c

So, my = -lx - n

y = -lx/m - n/m

Comparing with y = Mx + c,

M = -l/m

c = -n/m

We know that c = a/M

Mc = a

Putting the values of M and c,

-l/m x - n/m = a

ln/m^2 = a

ln = am^2