If the lines 2x_ 3y+7=0 3x+kx+5=0 cut the coordinate axes in concyclic points then k=
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Step-by-step explanation:
2x-3y+7=0
x=1 y=2 say
2(1)-3(2)+7=0
2-6+7=0
=3
3x+kx+5=0
3(1)+k(1)+5
3+k+5=0
k=-8
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