if the m^th term of an Ap is1/n and the n^th term is 1/m show that the sum of MN terms is1/2(mn+1)
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Step-by-step explanation:
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Step-by-step explanation:
Am=1/n. 1
An=1/m. 2
From eq1
a+(m-1)d=1/n. 4
From eq1 2
a+(n-1)d=1/m. 5
Eq4-Eq5
We get
d=1/mn
Putting d=1/mn in eq 1 we get
a =1/mn now
S(mn)=mn/2{2a +(mn-1)d}
Substitute a=1/mn and d=1/mn
We get
S(mn)=1/2(mn+1)
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