Question

If the machine boat can carry 7000 kg fish in a trip, how much fish it can carry in 5 such trips? PLEASE ANSWER IN LONG FORM AND FAST THAN I FOLLOW YOU​

Answer 1

Answer:

the total weight of fish in 1trip= 7000kg

the no. of trips=5

the weight of fish in 5trips=7000×5=35000kg

Step-by-step explanation:

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Answer 2

$\huge\mathbb\green{ANSWER}$

A/q.

1 Trip = 7000

5 Trips = ???

So, We have to Multiple the given number for the answer...

→ $\:5 \: ×\: 7000$

→ 35000

So answer is...$\green{35000}$

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