If the measure of two diagonals of a rhombus are 24 cm and 18 cm, then the perimeter of the
rhombus
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Given :
- If the measure of two diagonals of a rhombus are 24 cm and 18 cm.
To Find :
- The perimeter of rhombus = ?
Answer :
Finding Perimeter of a Rhombus :
- Given the lengths of the two diagonals of a rhombus, let's call them 'x' and 'y', the perimeter of the rhombus is given by:
➝ Perimeter of rhombus = 2√(x)² + (y)²
- The values of the diagonals provided by the question are x = 24 cm, y = 18 cm, thus the perimeter is:
➝ Perimeter of rhombus = 2√(24)² + (18)²
➝ Perimeter of rhombus = 2√576 + 324
➝ Perimeter of rhombus = 2√900
Taking square root of √900 :
➝ Perimeter of rhombus = 2 × 30
➝ Perimeter of rhombus = 60 cm
- Hence,the perimeter of rhombus is 60 cm.
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Properties of rhombus :
- All sides are congruent.
- Consecutive sides of rhombus are congruent.
- The diagonals of a rhombus are perpendicular
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