if the molecular mass of carbonate of divalent metal M is 100u then molecular mass of Hydroxide of the same metal will be
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Let the metal is M, so the formula of its carbonate is MCO3.
Molar mass of MCO3=x+12+3×16
=(x+60)g/mol
(Let atomic mass of M is x.)
∵448cc(448mL)CO2 is produced from carbonate =2g.
∴22400ccCO2 will be obtained from carbonate =4482×22400=100g
∴100=x+60
x=100−60=40g/mol
Eq. wt. of metal =240=20gequiv−1
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