If the nth terms of an AP is (2x-1), find the sum of first the n number of terms of the AP.
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For AP, an = a+ (n-1)d = 2n-1
a1 = 2-1 = 1
a2 = 4-1 = 3
Common difference , d = 3-1 = 2
Sum of n terms = (n/2)(2a + (n-1)d)
= (n/2)(2+(n-1)2)
= (n/2)(2+2n-2)
= (n/2)2n
= n2
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