Question

If the number of molecules in a given sample of sulphur dioxide (SO2) is 3.011 x 10^23,
calculate the following (Atomic mass of sulphur = 32 u, O = 16 u)
a) The number of moles in the given sample.
b) Mass of sulphur dioxide in the given sample.
c) Number of oxygen atoms in the given sample.

Answer 1

If the number of molecules in a given sample of sulphur dioxide ($SO_{2}$) is $3.011 \times 10^{23}$

Explanation:

a) The number of moles in the given sample.

$6.022 \times 10 ^{23}$ molecules of $SO_{2}$ = 1 mole of $SO_{2}$

So, $3.011  \times 10^{23}$ molecules of $SO_{2}$= $\frac{1}{6.022 \times 10 ^{23}} \times 3.011 \times 10 ^{23}$

mole of $SO_{2}$ = 0.5 moles of  $SO_{2}$

b). Mass of sulphur dioxide in the given sample.

1 mole of $SO_{2} = 32 + 2 \times 16 = 64 gm$

So, 0.5 mole of sample of  SO2 = 64 x 0.5 = 32 gm

c). Number of oxygen atoms in the given sample.

Mass of oxygen in $64 gm =  \frac{32}{64} \times 100 =50\%$

Hence, mass of $O_{2}$ atoms in given sample $(32 gm) = \frac{32 \times 50}{100}  = 16 gm$

Learn more about Analytical questions:

If the number of molecules in a given sample of sulphurdioxidein 3.011*10^23.calculate:

1.the number of moles in the given sample

2.mass of sulphurdioxide in the given sample

3.no.of oxygen atoms in the given sample

https://brainly.in/question/8379238

Answer 2

Explanation:

a).6.022 x 10 23 molecules of SO 2 = 1 mole of SO2

So, 3.011 x 10 23 molecules of SO 2 = (1/6.022 x 10 23 ) x 3.011 x 10 23 mole of SO2 = 0.5 moles of SO2

b). 1 mole of SO2 = 32 + 2 x 16 = 64 gm

So, 0.5 mole of sample of SO2 = 64 x 0.5 = 32 gm

c). Mass of oxygen in 64 gm = (32 / 64) x100 = 50 %

hence, mass of oxygen atoms in given sample (32 gm) = 32 x 50/100 = 16 gm