If the numbers 3k+1 ,7k+1 and 12k-5 are in AP ,then find the value of k
ayin15:
Is the answer 3
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It is given that 3k+4 , 7k +1 , 12k-5 are in A.P
Common difference is equal.
--> 7k +1 - (3k +4) = 12k-5 - (7k+1)
--> 7k +1 - 3k -4 = 12k -5 - 7k - 1
-->4k-3 = 5k-6
-->k = 3
Hope it helps...
...
Common difference is equal.
--> 7k +1 - (3k +4) = 12k-5 - (7k+1)
--> 7k +1 - 3k -4 = 12k -5 - 7k - 1
-->4k-3 = 5k-6
-->k = 3
Hope it helps...
...
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