if the numbers n-2, 4n-1 & 5n+2 are in AP find the value of n
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Topic:- Arithmetic Sequence or Progression
Let to T1=n-2
Let to be T2=4n-1
Let to be THE=5n+2
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Now...
T2-T1=T3-T2
4n-1-(n-2)=5n+2-(4n-1)
4n-1-n+2=5n+2-4n+1
4n-n+2-1=5n-4n+2+1
3n+1=n+3
3n-n=3-1
2n=2
n=2/2
n=1
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N=1
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Topic:- Arithmetic Sequence or Progression
Let to T1=n-2
Let to be T2=4n-1
Let to be THE=5n+2
=========================
Now...
T2-T1=T3-T2
4n-1-(n-2)=5n+2-(4n-1)
4n-1-n+2=5n+2-4n+1
4n-n+2-1=5n-4n+2+1
3n+1=n+3
3n-n=3-1
2n=2
n=2/2
n=1
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N=1
=============
Anonymous:
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