Question

If the numerical value of a diverging lens is 40 cm find its power in new Cartesian sign convention​

Answer 1

Answer:

it is the diverging lens or concave lens. Focal length =- 20 cm (lens is convave hence if is -ve) power P=f/1= -20cm / 100

Answer 2

The power of the lens is -2.5 D

Explanation:

Given:

A diverging lens has focal length 40 cm

To find out:

The power of the lens in Cartesian sign convention

Solution:

A diverging lens is nothing but a concave lens

The focal length of concave lens is negative as per sign convention

Therefore, the focal length of the lens = -40 cm

We know that if the focal length of a lens is $f$ m then its power $P$ is given by

$P=\frac{1}{f}$ Diopter

Where focal length is in metre

Therefore, the power of the lens

$P=\frac{1}{-40\times 10^{-2}}$ D

$\implies P=-2.5$ D

Hope this answer is helpful.

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