Question

if the perimeter of a field in the form of a parallelogram is 160m and one of its sides is 50m what are the measures of the other sides

Answer 1

Let the parallelogram be ABCD

Then, BC = 50

And also, AD = BC
AD = 50

Let, AB = x
then, CD= AB
So, CD = X

Perimeter = 160

Then, BC + AD + AB + CD = 160
50 + 50 + x + x = 160
100 + 2x = 160
2x = 160 - 100
x = 60 / 2
x = 30

Then, AB = CD = 30

Therefore the sides of parallelogram
are 50, 50, 30, and 30.

Answer 2

Step-by-step explanation:

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