If the perimeter of a sector of a circle of radius 6.5 cm is 29 cm, then its area is
(a)58 cm²
(b)52 cm²
(c)25 cm²
(d)56 cm²
Answers
Answer:
The Area of sector of a circle is 52 cm² .
Among the given options option (b) 52 cm² is the correct answer
Step-by-step explanation:
Given :
Perimeter of a sector of a circle,P = 29 cm
Radius of a circle = 6.5 cm
Perimeter of the sector ,P = length of the arc + 2× radius
P = θ/360° × 2πr + 2r
29 = θ/360° × 2 × 22/7 × 6.5 + 2 × 6.5
29 = θ/360° × 44/7 × 6.5 + 13
29 - 13 = θ/360° × 286/7
16 = θ/360° × 286/7
θ/360° = 16 × 7/286
θ/360° = 112/286 ……(1)
Area of sector of a circle, A = θ/360° × πr²
A = (112/286) × 22/7 × 6.5 × 6.5
[From eq 1]
A = 676/13
A = 52 cm²
Area of sector of a circle = 52 cm²
Hence, the Area of sector of a circle is 52 cm²
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Solution:
Let r, l are radius and length
of an arc of a sector .
1) perimeter (P) = 29 cm [given]
=> l+2r = 29
=> l = 29 - 2r
=> l = 29 - 2×6.5 [r=6.5cm ]
=> l = 29 - 13
=> l = 16 ----(2)
2)Area of the sector( A )= lr/2
= (16 × 6.5 )/2
= 8 × 6.5
= 52 cm²
Therefore,
Option (b) is correct.
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