if the perimeter of a semi circular protractor is 36cm find the it's diameter
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Answered by
3
In this question,pie×r=36m
so,r=36×7/22=126/11cm
So,diameter=126/11×2=22.9cm
so,r=36×7/22=126/11cm
So,diameter=126/11×2=22.9cm
Answered by
11
this is the required solution.
perimeter of the protactor =diameter+semi arc
36 = 2r + πr
⇒ 36 = r(2+π)
⇒ 36/(2+π) = r
⇒ 36/(2+22/7) =r
⇒ 36*7/(14+22) =r
⇒ 252/36 =r
∴r = 7
therefore, diameter=2r=14 cm
perimeter of the protactor =diameter+semi arc
36 = 2r + πr
⇒ 36 = r(2+π)
⇒ 36/(2+π) = r
⇒ 36/(2+22/7) =r
⇒ 36*7/(14+22) =r
⇒ 252/36 =r
∴r = 7
therefore, diameter=2r=14 cm
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