If the perimeter of a triangle formed by the
straight line 4x+ 3y = -k with x and y axis is 24 unit,
then find the value of k.
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Answer:
Step-by-step explanation:
=|k|(16+9)/(16(9))−−−−−−−−−−−−−√=|k|25/144−−−−−−√=|5k/12|
The perimeter is 24:
|k/3|+|k/4|+|5k/12|=24
The arguments to the absolute value are all the same sign so we can write this:
k/3+k/4+5k/12=±24
k=±2413+14+512=±2412/12=±24✓
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