if the point -2,4 lies on the graph of the equation y=ax+5 then find the value of a
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Answered by
3
Since, the point (-2,4) lie in second quadrant,
Hence x = -2 & y = 4
Y = ax + 5
4 = a(-2) + 5
4 = -2a + 5
2a = 5 - 4
2a = 1
a = 1/2
Hence, a = 1/2
Hence x = -2 & y = 4
Y = ax + 5
4 = a(-2) + 5
4 = -2a + 5
2a = 5 - 4
2a = 1
a = 1/2
Hence, a = 1/2
Answered by
1
If the point (-2, 4) lies on the graph of y = ax + 5, then the value of a is 0.5.
Given,
The point (-2, 4), lies on the graph of y = ax + 5.
To find,
The value of a.
Solution,
Here, we can see that the point (-2, 4) is given to be lying on the line having equation
y = ax + 5 ...(1)
Now, we know that when a point lies on a line, or the line passes through a point, then the point satisfies the equation of the line.
It means substituting the point in the equation must satisfy the equation.
So, putting (-2, 4) in (1), we get,
4 = a(-2) + 5
⇒ 4 = -2a + 5
Rearranging and simplifying,
2a = 5 - 4
⇒ 2a = 1
⇒ a = 0.5.
Therefore, if the point (-2, 4) lies on the graph of y = ax + 5, then the value of a is 0.5.
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