Question

if the point (2k-3,k+2)lies on the graph of the equation 2x+3y+15-0,find the value of k​

Answer 1

Since the point lies on the graph, it must satisfy the equation.

Hence put the value of x and y i.e., (2k – 3, k + 2) in the equation 2x + 3y + 15 = 0

So, 2 (2k - 3) + 3(k + 2) + 15 = 0

4k - 6 + 3k + 6 + 15 = 0

7k = -15

k = -15/7