if the point (2k-3,k+2) lies on the line 2x+3y+15=0 find the value of k
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Answered by
6
put
x= 2k-3 and y = k+2
then
2(2k-3)+3(k+2)+15=0
4k-6+3k+6+15=0
7k+15=0
k= -15/7
x= 2k-3 and y = k+2
then
2(2k-3)+3(k+2)+15=0
4k-6+3k+6+15=0
7k+15=0
k= -15/7
Rohitdadel:
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Answered by
5
Take,
x=2k-3 and y=k+2
Substitute the values in the following equation
2x+3y+15=0
2(2k-3)+3(k+2)+15=0
4k-6+3k+6+15=0
7k+15=0
7k=-15
k=-15/7
x=2k-3 and y=k+2
Substitute the values in the following equation
2x+3y+15=0
2(2k-3)+3(k+2)+15=0
4k-6+3k+6+15=0
7k+15=0
7k=-15
k=-15/7
thx you so much
plz mark it brainliest if it's helpful
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