If the point (3,4) lies on the graph of linear equation 3y = ax+7 find the value of a.
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x=3 and y=4 then substitute X and y values in linear equation 3y=ax+7
3 (4)=a (3)+7
12=3a+7
12-7=3a
5=3a
a=5/3
3 (4)=a (3)+7
12=3a+7
12-7=3a
5=3a
a=5/3
star11111:
correct
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