If the polynomial 6x4 + 8x3- 5x2 + ax + +b is exactly divisible by the polynomial 2x2 - 5 , then find the value of a and b
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When we divide 6x4 + 8x3 – 5x2 + ax + b by the polynomial 2x2 – 5, we get
Quetient = 3x2 + 4x + 5
and Remainder = (20 + a)x + (25 + b)
Given, the polynomial 6x4 + 8x3 – 5x2 + ax + b is exactly divisible by the polynomial 2x2 – 5
So, the remainder should be zero
Hence, (20 + a)x + (25 + b) = 0
=> 20 + a = 0
=> a = -20
and 25 + b = 0
=> b = -25
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Quetient = 3x2 + 4x + 5
and Remainder = (20 + a)x + (25 + b)
Given, the polynomial 6x4 + 8x3 – 5x2 + ax + b is exactly divisible by the polynomial 2x2 – 5
So, the remainder should be zero
Hence, (20 + a)x + (25 + b) = 0
=> 20 + a = 0
=> a = -20
and 25 + b = 0
=> b = -25
If u like this plzz give brilliant
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