if the present age of a father is4 years more than 5 times the age of his son.if the father was 28 years old before 2years,find the present ages of father and son.
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at present age of son = x years
father age = 4 years more than 5times the age of the son
= 5x+4
Before 2 years
age of son = (x-2)
father age = (5x+4-2) = 5x +2
father was 28 years old before 2 years means
father age - son age =28
5x+2 - (x-2) =28
5x+2-x+2=28
4x+4 =28
4x=28-4
4x=24
x=24/4
x= 6
therfore
at present son age =x=6years
father age = 5x+4
= 5*6+4
=30+4
=34
father age = 4 years more than 5times the age of the son
= 5x+4
Before 2 years
age of son = (x-2)
father age = (5x+4-2) = 5x +2
father was 28 years old before 2 years means
father age - son age =28
5x+2 - (x-2) =28
5x+2-x+2=28
4x+4 =28
4x=28-4
4x=24
x=24/4
x= 6
therfore
at present son age =x=6years
father age = 5x+4
= 5*6+4
=30+4
=34
sandysana:
really great...good
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