Question

If the prime factorization of a natural number n is 2³ × 3² × 5² × 7, write the number of consecutive zeros in n.

Answer 1

number of consecutive zeros in n = 2

Step-by-step explanation:

Prime factors of a natural number n = 2³ × 3² × 5² × 7

So the number n will be = 2 * 2 * 2 * 3 * 3 * 5 * 5 * 7 = 12600

The number of consecutive zeros in the natural number 12600 is two.