Question

if the probability of winning a race of an athletes is 1/6 less than the twice the probability of losing the race . Find ghe probability of winning the race

Answer 1

Let the probability of not winning the race be P(E').

and probability of winning the race be P(E).

as according to question,

P(E)=2P(E')-1/6.........i

and as we know that,

=>The sum of the coming probability and not coming probability of same data is equal to 1

--> P(E) + P(E') = 1......ii

Now, putting the value of P(E)

P(E) + P(E') = 1

2P(E') - 1/6 + P(E') = 1

=> 3P(E') - 1/6 = 1

=> { 18P(E') - 1 }/6 = 1

=> 18 P(E') - 1 = 6

=> 18P(E') = 6 + 1

=> P(E') = 7/18

Now, the probability of not winning the race is 7/18

putting the value of P(E') in equation ii

P(E) + P(E') = 1

P(E) + 7/18 = 1

P(E) = 1-7/18

P(E) = ( 18 - 7 )/ 18

P(E) = 11/18

So, the probability of winning the race is =
$\frac{11}{18}$


@Altaf

Answer 2

Answer:

so see follow the below answer

Step-by-step explanation: