If the product of zeroes of 9xsquare+3x+p is 7 then p=
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Given :
7 is the product of zeroes of the polynomial : 9x²+ 3x+p.
To find :
Here, we shall find the value of p.
Solution :
We know that :
- Product of zeroes (αβ) of ax²+bx+c = c/a
When we compare 9x²+3x+p to ax²+bx+c (where a≠0), we get :
- a = 9
- b = 3
- c = p
So, according to the question :
- c/a = 7
- p/9 = 7
- p = 7 × 9
- p = 63
Therefore, p = 63 when 7 is the product of zeroes of the polynomial 9x²+3x+p.
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