If the quadratic equation ax² +bx + c = 0 has equal roots then find c in terms of a and b.
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Answered by
11
For a quadratic equation ax² + bx + c =0, the term b² - 4ac is called discriminant (D) of the quadratic equation because it determines whether the quadratic equation has real roots or not ( nature of roots).
D= b² - 4ac
So a quadratic equation ax² + bx + c =0, has
Two equal real roots, if b² - 4ac = 0 , then x= -b/2a or -b/2a
SOLUTION:
GIVEN:ax² + bx + c =0,
D= b² - 4ac
0 = b² - 4ac [ D= 0 , equal roots] given
b² - 4ac= 0
b² = 4ac
c = b² / 4a
Hence, the value of c in terms of a & b = c = b² / 4a.
HOPE THIS WILL HELP YOU...
D= b² - 4ac
So a quadratic equation ax² + bx + c =0, has
Two equal real roots, if b² - 4ac = 0 , then x= -b/2a or -b/2a
SOLUTION:
GIVEN:ax² + bx + c =0,
D= b² - 4ac
0 = b² - 4ac [ D= 0 , equal roots] given
b² - 4ac= 0
b² = 4ac
c = b² / 4a
Hence, the value of c in terms of a & b = c = b² / 4a.
HOPE THIS WILL HELP YOU...
Answered by
3
Given quadratic equation is:
ax² + bx + c = 0
We know that, when a given equation have equal roots then its discriminant is always equal to be zero.
⇒ D = 0
⇒ b² - 4ac = 0
⇒ - 4ac = -b²
⇒ 4ac = b²
⇒ c = b²/4a
Please mark as brainliest
ax² + bx + c = 0
We know that, when a given equation have equal roots then its discriminant is always equal to be zero.
⇒ D = 0
⇒ b² - 4ac = 0
⇒ - 4ac = -b²
⇒ 4ac = b²
⇒ c = b²/4a
Please mark as brainliest
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