Question

if the radii of circular ends of frustum of a cone are 17 cm and 15cm and its height is 4 cm then find the slant height of frustum ( in cm )?

Answer 1

hey mate !!

here' is your answer !!


Answer

5cm


in the questions we find the slant height of frustum.


in the questions GIVEN,


upper radius of frustum of a cone R equal to 17cm.

and,

Lower radius of frustum of a cone r equal to 15 cm.

and here also given,

the height of the frustum of a cone h equal to 4cm.

here' we using formula ,

slant height of frustum of a cone

${l}^{2} = \: \sqrt{ {h}^{2} + ( {R - r)}^{2} } \\ \\ = \sqrt{ {4}^{2} + ( {17 - 15)}^{2} } \\ \\ = \sqrt{16 + 9} \\ \\ { \sqrt{25} } \\ \\ = 5$

therefore the required slant height of frustum is 5cm.


be brainly

Answer 2

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In the questions we have to

find the slant height of frustum.

Given,

$upper \: radius \: of \: frustum \: of \: cone \: (\:r )\: = 17cm$

$</p><p>Lower \: radius \: of \: frustum \: of \: a \: cone( \: r) = 15cm$

And here also given,

$the \: height \: of \: the \:frustum \: of \: a \: cone( h ) = 4cm$

Using formula,

$slant \: height \: of \: frustum \: of \: a \: cone$

$⟹ {l}^{2} = \sqrt{ {h }^{2 + (R - {r}^{2} )} }$

$= \sqrt{ {4}^{2 + (17 - {15)}^{2} } }$

$= \sqrt{16 + 9}$

$= \sqrt{25}$

$= 5$

Therefore the required slant height of frustum is 5cm.