Math, asked by DavidSupierior1049, 9 months ago

If the radius of a sphere is doubled, what is the ratio of the volume of the first sphere to that of the second sphere?

Answers

Answered by nikitasingh79
1

Given :  Radius of a sphere is doubled.

Let 'r' be the radius of the first sphere.

& the radius of the second sphere be '2r'

Volume of a sphere = (4/3)πr³

Ratio of the volume of the first sphere (V1)  to that of the second sphere (V2) = (4/3)πr³/(4/3)π(2r)³

V1/V2 = r³/(2r)³

V1/V2 = ⅛

V1 : V2 = 1 : 8

Hence, the ratio of the volume of the first sphere to that of the second sphere is 1 : 8.

HOPE THIS ANSWER WILL HELP YOU…..

Similar questions :

If the ratio of volumes of two spheres is 1: 8, then the ratio of their surface areas is

A. 1 : 2

B. 1 : 4

C. 1 : 8

D. 1 : 16

https://brainly.in/question/15912816

The ratio of the total surface area of a sphere and a hemisphere of same radius is

A. 2 : 1

B. 3 : 2

C. 4 : 1

D. 4 : 3

https://brainly.in/question/15912602

Answered by Anonymous
1

Step-by-step explanation:

Given :  Radius of a sphere is doubled.

Let 'r' be the radius of the first sphere.

& the radius of the second sphere be '2r'

Volume of a sphere = (4/3)πr³

Ratio of the volume of the first sphere (V1)  to that of the second sphere (V2) = (4/3)πr³/(4/3)π(2r)³

V1/V2 = r³/(2r)³

V1/V2 = ⅛

V1 : V2 = 1 : 8

Similar questions