If the radius of the octahedral void is r and radius of the atoms in close-packing is R, derive relation between r and R.
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Answered by
3
Let take r and R are the radii of the octahedral site and atoms respectively,
then use Pythagoras theorem we get
(2R)2 =(r+R )2 + (r+R)2
4R2 = 2(r+R )2
divide by 2 we get
2R2 =(r+R)2
take root both sides we get
R/2 =r+R
R/2-R=r
R=r(/2 -1)
value of /2 =1.414
r=R (1.414-1)
R=0.414 R
then use Pythagoras theorem we get
(2R)2 =(r+R )2 + (r+R)2
4R2 = 2(r+R )2
divide by 2 we get
2R2 =(r+R)2
take root both sides we get
R/2 =r+R
R/2-R=r
R=r(/2 -1)
value of /2 =1.414
r=R (1.414-1)
R=0.414 R
Answered by
3
Using Pythagoras theorem we get;
(2R)2 = (R+r)2 +(R+r)2;
4R2 = 2(R+r)2;
We divide by 2;
2R2 = (R+r)2;
Take root both side we get;
R√2 =R+r;
R√2 – R = r;
r = R(√2–1);
and √2= 1.414;
r = R(1.414–1) ;
r = 0.414 R
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