Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.
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Ferric oxide crystallizes in hcp and the oxide ions are present in the lattice sites, so the number of atoms =6;
ferric ions occupy the octahedral voids, and the occupancy = 2/3;
no of octahedral voids = 6;
octahedral voids occupied = 2*6/3 = 4;
therefore the formula of ferric oxide is;
Fe 4 O6 or Fe2O3.Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell.
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Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.
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